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Simplifying b4 + -3b2 + -4 = 0 Reorder the terms: -4 + -3b2 + b4 = 0 Solving -4 + -3b2 + b4 = 0 Solving for variable 'b'. Factor a trinomial. (-1 + -1b2)(4 + -1b2) = 0 Factor a difference between two squares. (-1 + -1b2)((2 + b)(2 + -1b)) = 0Subproblem 1
Set the factor '(-1 + -1b2)' equal to zero and attempt to solve: Simplifying -1 + -1b2 = 0 Solving -1 + -1b2 = 0 Move all terms containing b to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -1b2 = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -1b2 = 0 + 1 -1b2 = 0 + 1 Combine like terms: 0 + 1 = 1 -1b2 = 1 Divide each side by '-1'. b2 = -1 Simplifying b2 = -1 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.Subproblem 2
Set the factor '(2 + b)' equal to zero and attempt to solve: Simplifying 2 + b = 0 Solving 2 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + b = 0 + -2 b = 0 + -2 Combine like terms: 0 + -2 = -2 b = -2 Simplifying b = -2Subproblem 3
Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2Solution
b = {-2, 2}
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